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    supporting cylinder Sold to Algeria

    Release time:2023-11-27 15:08:29 Hits: Current position: Home > News

    This article mainly introduces:

    Algeria hydraulic cylinder,supporting cylinder manufacturer,supporting cylinder

    Algeria supporting cylinder

    (Algeria supporting cylinder,produced by Hengyu Hydraulic Co., Ltd)

    supporting cylinder are widely used in Algeria,because of smooth movement,high work efficiency,excellent fatigue and impact resistance.So our company has designed supporting cylinder for customers from Algeria.

    Introduction to supporting cylinder:

    supporting cylinder use should try to avoid sealing belt into the supporting cylinder. As a simple sealing material, polytetrafluoroethylene plastic sealing tape is often used in installation and inspection, and if the winding method of the linear and ribbon-shaped sealing material is wrong, the sealing tape will be cut off and enter the supporting cylinder. The wire belt seal will not have any effect on the winding of the sliding part, but it will cause the check valve of the supporting cylinder to fail to operate or the buffer regulating valve can not be adjusted to the end. For the circuit, it may cause the action of the reversing valve, the relief valve and the reducing valve to fail.

    In the case of serious wear on the inner surface of the supporting cylinder, or when there is a deep longitudinal tensile mark, it should be mapped according to the physical object and re-produced by the professional manufacturer according to the supporting cylinder manufacturing process for replacement. The supporting cylinder can also be repaired with TS311 antiwear repair agent. TS311 anti-wear repair agent is mainly used for the repair of worn and slipped metal parts.

    supporting cylinder and hydraulic station selection: Select the type and structure of the supporting cylinder according to the operation requirements of the main engine. According to the external load force borne by the supporting cylinder, such as gravity, friction force of the external mechanism, inertia force and working load, determine the load change law of the supporting cylinder in each stage of the stroke and the power value that must be provided. Determine the diameter of the piston and piston rod according to the working load of the supporting cylinder and the selected oil working pressure. the flow rate of the hydraulic pump is determined according to the movement speed of the supporting cylinder, the diameter of the piston and the piston rod.

    supporting cylinder abnormal sound, hysteresis phenomenon cause and elimination method: the piston rod is extended with abnormal sound and hysteresis, if the supporting cylinder is placed for a period of time, the supporting cylinder may enter the air, and the movement can be normal after dozens of repeated movements. If it still cannot be eliminated, check whether the load is aligned with the axis of the piston rod; Retracted piston rod installation helps to align the load with the piston rod. If the flow is unstable, it will also lead to abnormal movement of the piston rod. Check the relevant components of the hydraulic system.

    Answers to some questions about supporting cylinder:

    How to determine the rated working pressure of the hydraulic cylinder?
    Under normal circumstances, the working pressure is determined according to the size of the load and the installation space (the allowable diameter of the cylinder). In some special occasions, the smaller the cylinder, the better, the pressure level must be increased. The cylinder pressure is related to the estimated cost. The higher the pressure, the thicker the wall, the higher the cost, but conversely, the lower the pressure, the larger the diameter of the cylinder (when the same thrust) is required, the same high cost. Therefore, the rated pressure of the cylinder is concentrated in about 35 mpa, taking into account the cylinder diameter and wall thickness.

    Why is a light cylinder less productive than a heavy cylinder at the same oil pressure?
    f=ps Under the same pressure, the larger the area, the greater the output, but the maximum pressure can not exceed the system engineering pressure of the cylinder!

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